A particle executes simple harmonic motion of ampliltude A. At what distance from the mean position is its kinetic energy equal to its potential energy?

A particle executes simple harmonic motion of amplitude A. (i) At what distance from the mean positio is its kinetic energy equal to its potential energy? (ii) At what points is its speed half the maximum speed?

A particle executes simple harmonic motion of amplitude A (i) At what distance from the extreme positino is its kinetic energy equal to half its potential energy ? (ii) At what position from the extreme position is its speed half the maximum speed.

A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

(a) A particle executes simple harmonnic motion with an amplitude of 10cm . At what distance from the mean position are the kinetic and potential energies equal? (b) The maximum speed and acceleration of a particle executing simple harmonic motion are 10m//s and 50cm//s . Find the position(s) of the particle when the speed is 8cm//s .

In a SHM distance from mean position where kinetic energy equals potential energy is

A particle executes simple harmonic motion of a certain amplitude A. Calculate the distance from the mean position where the kinetic energy of particle is equal to its potential energy. Also, find the points where the speed of the particle is 1/3 of its maximum speed.

A particle executes SHM of amplitude A. At what distance from the mean position is its KE equal to its PE ?

A particle executes simple harmonic motion with an amplitude 9 cm. At what displacement from the mean position, energy is half kinetic and half potential ?