Arrange the following in the order of increasing boiling points.
`CH_(3)CH_(2)CHO(A), CH_(3)CH_(2)CH_(2)CH_(2)OH(B)`,
`CH_(3)CH_(2)OCH_(2)CH_(3)(C), CH_(3)CH_(2)CH_(2)CH_(3)(D)`.

Explanation

Molecular masses of compounds A, B, C and D are almost same (72-74).
Compound (B) is an alcohol, associated with extensive inter molecular hydrogen bonding. Hence its boiling point is highest. (A) an aldehyde, is more polar than (C), Which is an ether. (D) is an alkane and possesses only weak van der waals forces. Hence its boiling point is least. Hence the boiling point order is : `B gt A gt C gt D`.