A hydrocarbon `C_(5)H_(10)` does not react with chlorine in dark but gives a single monochloro-compound `C_(5)H_(9) Cl` in bright sunlight . Identify the hydrocarbon .

A hydrocarbon , C_5 H_(12) gives only one monochlorination product .Identify that hydrocarbon .

A hydocarbon having molecular formula C_(8)H_(16) absorbed no hydrogen during hydrogenation. The hydrocarbon is

Among the three isomeric alkanes (C_5 H_(12)), identify the one that on chlorination yields A single monochloride

A compound "X" has molecular formula C_5H_(9) Cl . It does not react with bromine in C Cl_4 . On treatment with strong base it produces single compound "Y" (C_5H_8) and reacts with Br_(2)(aq) . Ozonolysis of "Y" produces a compound C_5H_(8)O_2 . The structure of X is

Compound (A) C_5H_(10) does not dissolve in cold dil. H_2SO_4 . What is (A) ?

The heat of combustion of hydrocarbon C_(x)H_(y) is ''a'' calories and heat of formation of CO_(2) and H_(2)O are ''b'' and 'c' calories respectively then the heat of formation of hydrocarbon C_(8)H is (in calories)

The total number of structural isomers possible for hydrocarbon C_(5)H_(10) is:

A hydrocatbon with formula C_8H_(18) He gives one monochloro derivative. The hydrocarbon is: