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At constant temperature 80% AB dissociat...

At constant temperature 80% AB dissociates into `A_(2)` and `B_(2)` then the equilibrium constant for `2AB_((g)) harr A_(2(g)) +B_(2(g))`

A

1

B

0.25

C

16

D

4

Text Solution

Verified by Experts

The correct Answer is:
D

`K=(0.4 xx 0.4)/((0.2)^(2))=4`
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