Home
Class 11
PHYSICS
A coin moves in a circular path in a rou...

A coin moves in a circular path in a rough rotating horizontal surface which has an angular acceleration `alpha`

A

power delivered by the friction on the coin is positive.

B

power delivered by centripetal force on the particle is zero.

C

work done by the contacting frictional force on the system (disc + surface) is negative.

D

Tangential acceleration of the coin is directly proportional to the rate at which the power is being delivered by the external agent.

Text Solution

Verified by Experts

The correct Answer is:
A, B
Promotional Banner

Topper's Solved these Questions

  • WORK -POWER-ENERGY

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-VI POWER) (LEVEL-II MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|4 Videos

  • WORK -POWER-ENERGY

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-VII VERTICAL CIRCLE AND SPRINGS) (LEVEL -I STRAIGHT OBJECTIVE TYPE QUESTIONS)|11 Videos

  • WORK -POWER-ENERGY

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-V MECHANICAL ENERGY AND ITS CONSERVATION) (LEVEL -II INTEGER TYPE QUESTIONS)|2 Videos

  • VISCOSITY

    AAKASH SERIES|Exercise Questions for Descriptive Answers|3 Videos

  • WORK POWER ENERGY

    AAKASH SERIES|Exercise EXERCISE - 3|61 Videos

Similar Questions

Explore conceptually related problems

A particle moves in a circular path such that its speed v varies with distance as V= alphasqrt(s) where alpha is a positive constant. Find the acceleration of the particle after traversing a distance s.

A horizontal force applied on a body on a rough horizontal surface produces an acceleration 'a'. If coefficient of friction between the body & surface which is m is reduced to m/3, the accele-ration increases by 2 units. The value of m is

A particle of mass M moves in a circular path of radius r with a constant speed equal to V. Then its centripetal acceleration is