What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? `(Y=2xx10^(11)Nm^(-2))`

Explanation

`r = 1/2 xx 10^(-3) m , L = 2m, Y = (Mg)/(pi r^2) L/e`
`M = (Y(pi r^2)e)/(gL) = (2 xx 10^11 xx pi (1/2 xx 10^(-3))^2 xx 1 xx 10^(-3))/(9.8 xx 2)`
` = (pi xx 10^2 )/(9.8 xx 4) = (100pi)/(39.2) = 8.015 kg `