Home
Class 11
PHYSICS
N(lt100) molecules of a gas have velocit...

N(`lt`100) molecules of a gas have velociteis 1,2,3……N km/s respectively.Then

A

rms speed and average speed of molecules are same

B

Ration of rms speed and average speed is
`sqrt(((2N+1)(N+1))/(6N))`

C

Ration of rms speed and average speed is
`sqrt(((2N+1)(N+1))/(6))`

D

Ration of 'rms' speed and average speed of molecules is `sqrt((2(2N+1))/(3(N+1)))`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    AAKASH SERIES|Exercise Problems|12 Videos
  • KINETIC THEORY OF GASES

    AAKASH SERIES|Exercise Exercise -I|50 Videos
  • KINETIC THEORY OF GASES

    AAKASH SERIES|Exercise EXERCISE-3(Kinetic Theory of an ideal gas)|4 Videos
  • KINEMATICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED)) (Integer Type Questions)|12 Videos
  • LAWS OF MOTION

    AAKASH SERIES|Exercise PRACTICE EXERCISE|108 Videos

Similar Questions

Explore conceptually related problems

Four molecules of a gas have speeds 1,2,3 and 4 km//s . Find the rms speed of the gas molecule.

The most probable velocity of the molecules of a gas is 1 km/sec. The R.M.S velocity of the molecules is

A gas mixture contains n_1 moles of a monoatomic gas and n_2 moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent (C_p)/(C_v) for this gas mixture is 1.5, then the ratio n_1/n_2 will be

At T(K), a hypothetical gas consisting of 100 molecules has the following distribution of velocities. (N = Number of molecules, V = velocity in cm s^(-1) ). The most probbable velocity (in cm s^(-1) ) for this gas is

If S_(1), S_(2),S_(3), are the sums of first n natural numbers their squares and their cubes respectively, then S_(3) (1 + 8 S_(1)) =

If S_(n) represents the sum of n terms of G.P whose first term and common ratio are a and r respectively, then s_(1) + s_(2) + s_(3) + …+ s_(n) =