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I= int x "In" (1+(1)/(x) ) dx....

`I= int x "In" (1+(1)/(x) ) dx`.

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The correct Answer is:
`I= int x "In" (1+ (1)/(x) ) dx= (1)/(2) (x^(2) - 1) "In" (x+1) - (x^2)/( 2) "In" x+ (x)/(2) +C`.
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