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Show that int0^pifx(sinx)dx=pi/2int0^pif...

Show that `int_0^pifx(sinx)dx=pi/2int_0^pif(sinx)dxdot`

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The correct Answer is:
`2 int_(0)^(pi) x f (sin x) dx = pi int_(0)^(pi) f (sin x) dx`
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