A body falling to the ground from a state of rest acquires a velocity `v_(1)= sqrt(2gs_(1))` on covering a vertical path `s= s_(1)`. Show that the average velocity `v_(m)` over this path is equal to `(2v_(1))/(3)`

A body travels a distance s_(1) with vleocity v_(1) and distance s_(2) with velocity v_(2) in the with velocity v_(2) . Calculate the average velocity.

The body travels a distance s_(1) with velcity v_(1) and s_92) with velcity v_(2) in the same directin. Calculate the average velocity of the body .

A body travelling along a straight line traversed one-third of the total distance with a velocity v_1 . The remaining part of the distance was covered with a velocity v_2 for half the time and with velocity v_3 for the other half of time. The mean velocity averaged over the whole time of motion

A body covers a total distance of 3s . The first s is covered with a velocity u the second s with V and the last s with omega . Then, the average velocity during the whole journey is

A particle of mass m is moving with a uniform velocity v_(1) . It is given an impulse such that its velocity becomes v_(2) . The impulse is equal to

A body travels with velocity v_(1) for time t_(1) second and with velocity v_(2) for time t_(2) second in the same direction, fide the avetage velocity of the body.

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

If a body travels half the distance with velocity v_(1) and next half with velocity v_(2), then which one of the following will be the average velocity of the body?