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MnO(4)^(-)+8H^(+)+n e^(-)rarrMn^(2+)+4H(...

`MnO_(4)^(-)+8H^(+)+n e^(-)rarrMn^(2+)+4H_(2)O`
The value of n is 

Text Solution

Verified by Experts

The correct Answer is:
5
Total charge of L.H.S = Total change on R.H.S.
`(-1)+8+(-n)=+2 " or "n = 5`
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