The moment of inertia of a flywheel making 300 revolutions per minute is 0.3 `kgm^2` . Find the torque required to bring it to rest in 20s.

Explanation

Torque `tau = I alpha = I((omega_(2)-omega_(1)))/(t)`
`therefore tau = (0.3xx(0-10pi))/(20) = -0.15 pi = -0.471 Nm`.