The frequency of a particle performing SHM is 12 Hz. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme position. Its equation for displacement is

Options

A. `x = 0.04 cos (24 pi t + (pi)/(6))`
B. `x = 0.04 sin (24 pi t)`
C. `x = 0.04 sin (24 pi t + (pi)/(6))`
D. `x = 0.04 cos (24 pi t)`

Answer

C