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The frequency of a particle performing S...

The frequency of a particle performing SHM is 12 Hz. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme position. Its equation for displacement is

A

`x = 0.04 cos (24 pi t + (pi)/(6))`

B

`x = 0.04 sin (24 pi t)`

C

`x = 0.04 sin (24 pi t + (pi)/(6))`

D

`x = 0.04 cos (24 pi t)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The frequency of a particle performing SHM is 12 hz,. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme positon. Its equation for displacement is

    A
    `x=0.04 cos (24pi t +(pi)/6)`
    B
    `x=0.04sin(24pit)`
    C
    `x=o0.04sin(24pit+(pi)/6)`
    D
    `x=0.04cos (24pit)`

  • The frequency of a particle performing SHM is 12 hz,. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme positon. Its equation for displacement is

    A
    `x=0.04 cos (24pi t +(pi)/6)`
    B
    `x=0.04sin(24pit)`
    C
    `x=o0.04sin(24pit+(pi)/6)`
    D
    `x=0.04cos (24pit)`

  • A particle is performing SHM. Its

    A
    root mean square velocity is times of its maximum velocity.
    B
    mean velocity over a complete cycle is equal to times of its maximum velocity.
    C
    mean velocity calculated during the motion from left extreme position to right extreme position is equal to times of its maximum velocity.
    D
    None of these

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