The time period of a simple pendulum is T. When the length is increased by 10 cm, its period is `T_1`. Then , relation between T,`T_1` and `T_2` is,

Options

A. `(2)/(T^(2)) = (1)/(T_(1)^(2)) + (1)/(T_(2)^(2))`
B. `(2)/(T^(2)) = (1)/(T_(1)^(2)) - (1)/(T_(2)^(2))`
C. `2T^(2) = T_(1)^(2) + T_(2)^(2)`
D. `2T^(2) = T_(1)^(2) - T_(2)^(2)`

Answer

C