Home
Class 11
PHYSICS
Two forces F(1) and F(2) are acting at a...

Two forces `F_(1) and F_(2)` are acting at a point, having resultant as F. If `F_(2)` is doubled F is also doubled. If `F_(2)` is reversed then also F is doubled. If `F = 16 sqrtN, F_(1) = sqrt2N and F_(2) = n` then find n

Text Solution

Verified by Experts

The correct Answer is:
3
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-II (Resolution of vectors) (Straight Objective Type Questions)|12 Videos
  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III (Multiplication of Vectors) (Straight Objective Type Questions)|8 Videos
  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet (Exercise-I) (Addition of Vectors) (More than correct answer type Questions)|2 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED))|14 Videos
  • VISCOSITY

    AAKASH SERIES|Exercise Questions for Descriptive Answers|3 Videos

Similar Questions

Explore conceptually related problems

If f:NtoR is defined by f(1) = - 1 and f(n+1) = 3f(n) + 2 for nge1 , then f is

When force F_(1), F_(2), F_(3) are acting on a particle of mass m such that F_(2) and F_(3) are mutually perpendicular, then the particle remains stationary. If the force F_(1) is now removed then acceleration of the particle is

The work done by a force F_(1) is larger than the work done by another force F_(2) . Is it necessary that power delivered by F_(1) is also than that of F_(2) ? Why ?

There are four forces acting at a point P produced by strings as shown in , which at rest . The forces F_(1) and F_(2) respectively:

A homogeneous rod of length 'L' is acted upon by two forces F_(1) and F_2 applied to its ends and directed opposite to each other. If F_(2) gt F_(1) then with what force 'F' will the rod be stretched at the cross-section at a distance 1 from the end where F_(1) is applied:

Find the derivative of the function If f (x) = mx + c and if f (0) = f ^(1) (0) =1 then find f (2).

Two blocks m_(1) and m_(2) are connected by a massless spring of force constant k F_(1) and F_(2) are two forces acting on m and m_1 and m_2 as shown. The arrangement is on a horizontal plane.