Home
Class 11
PHYSICS
The position vector of a moving particle...

The position vector of a moving particle at't' sec is given by `vecr = 3hati + 4t^(2)hatj - t^(3)hatk` . Its displacement during an interval of t = Is to 3 sec is

A

`hat(j) - hat(k)`

B

`3 hat(i) + 4 hat(j) - hat(k)`

C

`9 hat(i) + 36 hat(j) - 27 hat(k)`

D

`32 hat(j) - 26 hat(k)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III (Multiplication of Vectors) (Straight Objective Type Questions)|8 Videos

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III (Multiplication of Vectors) (More than correct answer type Questions)|1 Videos

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet (Exercise-I) (Integer Type Questions)|3 Videos

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED))|14 Videos

  • VISCOSITY

    AAKASH SERIES|Exercise Questions for Descriptive Answers|3 Videos

Similar Questions

Explore conceptually related problems

The position vector of a particle is given by r = 3t^(2)hati + 4t^(2)hatj + 7hatk m at a given time 't'. The net displacement of the particle after 10s is

The position vector of a particle is vecr = (a cos omega t)hati + (a sin omegat)hatj . the velocity of the particle is

The position of a particle is given by r=3.0thati + 2.0 t^(2)hatj + 5.0 hatk . Where t is in seconds and the coefficients have the proper units for r to be in metres, (a) Find v(t) and aft) of the particle, (b) Find the magnitude and direction ofv(t) at t = 1.0 s.

The position of a point in time 't' is given by x = 1 + 2t + 3t^(2) and y = 2 - 3t + 4t^(2) . Then its acceleration at time 't' is