Home
Class 11
PHYSICS
Two particles having position vectors ve...

Two particles having position vectors `vecr_1=(3hati+5hatj)m` and `r_2 =(-5hati + 3hatj) m` are moving with velocities `V_1 = (4hati +3hatj)m/s` and `V_2 = (-ahati + 4hatj) m/s` . If they collide after `2` s, the value of `a` is

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III (Multiplication of Vectors) (Straight Objective Type Questions)|8 Videos

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet Exercise-III (Multiplication of Vectors) (More than correct answer type Questions)|1 Videos

  • VECTORS

    AAKASH SERIES|Exercise Lecture Sheet (Exercise-I) (Integer Type Questions)|3 Videos

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED))|14 Videos

  • VISCOSITY

    AAKASH SERIES|Exercise Questions for Descriptive Answers|3 Videos

Similar Questions

Explore conceptually related problems

The resultant of the forces vecF_(1) = 4hati-3hatj and vecF_(2) = 6hati + 8hatj is

If the points with position vectors 60hati+3j, 40hati-8hatj and ahati-52hatj are collinear, then a is equal to

Area of a parallelogram formed by vectors (3hati-2hatj+hatk)m and (hati+2hatj+3hatk) m is