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A particle moves in the X-Y plane under ...

A particle moves in the X-Y plane under the action of a force `vec(F)` such that the value of its linear momentum `(vec(P))` at any time .t., and its components are `P_(X) = 2 cos t, P_(Y) = 2 sin t`. According to defination of force `vec(F) = (d vec(P))/(dt)`
The angle `.theta.` between `vec(F) and vec(P)` at a given time .t. will be

A

`theta = 0^(@)`

B

`theta = 30^(@)`

C

`theta = 90^(@)`

D

`theta = 180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
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