Home
Class 12
PHYSICS
For a given surface the Gauss.s Law is s...

For a given surface the Gauss.s Law is stated as `oint E.ds= 0`. From this we can conclude that:

A

E is necessarily zero on the surface

B

E is perpendicular to the surface at every point

C

the total flux through the surface is zero

D

the flux is only going out of the surface

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CHARGES AND FIELDS

    AAKASH SERIES|Exercise Exercise-II|56 Videos

  • ELECTRIC CHARGES AND FIELDS

    AAKASH SERIES|Exercise Practice Exercise|57 Videos

  • ELECTRIC CHARGES AND FIELDS

    AAKASH SERIES|Exercise Assess Your Self|13 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH SERIES|Exercise PRACTICE EXERCISEX|44 Videos

  • ELECTRIC FIELD AND POTENTIAL

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|32 Videos

Similar Questions

Explore conceptually related problems

The base sequence for a nucleic acid segment is given as GAG AGG GGA CCA. From this, it can be concluded that it is a segment of a

From the discussion related to Venktesh and Gaythri’s doubt, we can conclude that there are several ecosystems around’us. is A field, a pond or your school garden all are examples of the same??.

Aluminium does not react with water at room temperature but reacts with both dil . Hcl and NaOH solutions . Verify these statements experimentally . Write your observation with chemiscal equation , From these observations , can we concluds that Al is a metalloid ?

(a) Show that the normal component of electrostatic field has a discontinuity from one side of a charged surface to another given by (E_(2)-E_(1)).n = sigma/epsilon_(0) where hatn is a unit vector normal to the surface at a point and sigma is the surface charge density at that point. (The direction of hatn is from side 1 to side 2.) Hence, show that just outside a conductor, the electric field is sigma hatn //epsilon_(0) . (b) Show that the tangential component of electrostatic field is continuous from one side of a charged surface to another. [Hint: For (a), use Gauss’s law. For, (b) use the fact that work done by electrostatic field on a closed loop is zero.]

Two moles of liquid A(P_(A)^(0)=100 torr) and 3 moles of liquid B(P_(B)^(0)=150 torr) from a solution having vapour pressure of 120 torr. Based upon this observation one can conclude:

AAKASH SERIES-ELECTRIC CHARGES AND FIELDS-Exercise-I
  1. A force between the two stationary charges separated by certain distan...

    Text Solution

    |

  2. Which of the following statements are correct. (a) Electric lines of...

    Text Solution

    |

  3. For a given surface the Gauss.s Law is stated as oint E.ds= 0. From th...

    Text Solution

    |

  4. It is not convenient to use a spherical Gaussian surface to find the e...

    Text Solution

    |

  5. An ellipsoidal cavity is carved with in a perfect conductor. A positiv...

    Text Solution

    |

  6. If a charge is enclosed by the surface of the sphere then total flux e...

    Text Solution

    |

  7. A metallic shell has a point charge .q. kept inside its cavity. Which ...

    Text Solution

    |

  8. A charge of Q coulomb is placed on a solid piece of metal of irregular...

    Text Solution

    |

  9. Gauss.s law is true only if force due to a charge varies as:

    Text Solution

    |

  10. An electric diple is put in north-south direction in a sphere filled w...

    Text Solution

    |

  11. Two small spheres each carrying a charge q are placed r metre apart. I...

    Text Solution

    |

  12. Find the total flux due to charge q associated with the given hemisphe...

    Text Solution

    |

  13. A: A metallic shield in the form of a hollow shell may be built to blo...

    Text Solution

    |

  14. A thin spherical shell of radius R has charge Q spread uniformly over ...

    Text Solution

    |

  15. An electric dipole kept in a uniform electric field experiences

    Text Solution

    |

  16. The value of electric potential at any point due to any electric dipol...

    Text Solution

    |

  17. An electric dipole is plced at an angle of 30^(@) to a nonuniform elec...

    Text Solution

    |

  18. What is the angle between the electric dipole moment and the electric ...

    Text Solution

    |

  19. An electric dipole is kept in nonuiform electric field. It experiences

    Text Solution

    |

  20. Match List-I with List-II

    Text Solution

    |