A monochromatic light of wavelength `lamda` is incident on an isolated metallic sphere of radius a. The threshold wavelength is `lamda_(0)`, which is larger than `lamda`. Find the number of photoelectrons emitted before the emission of photo electrons stops.

Explanation

As the metallic sphere is isolated, it becomes positively charged when electrons are ejected from it. There is an extra attractive force on the photoelectrons. If the potential of the sphere is raised to V, the electron should have a minimuin energy W+eV to be able to come out. Thus, emission of photoelectrons will stop when
`(hc)/(lamda)=W+eV=(hc)/(lamda_(0))+eVorV=(hc)/(e)((1)/(lamda)-(1)/(lamda_(0)))`
The charge on the sphere needed to take its potential to V is `Q=(4piepsi_(0)a)V`
The number of electrons emitted is, therefore,
`n=(Q)/(e)=(4piepsi_(0)aV)/(e)=(4piepsi_(0)ahc)/(e^(2))((1)/(lamda)-(1)/(lamda_(0)))`