Light of described at a place by the equation `E=(100)[sin5xx10^(15)]t+sin(8xx10^(15))t]` falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.

Explanation

The light contains two different frequencies. The one with large frequency will cause photoelectrons with largest kinetic energy. This larger frequency is
`v=(omega)/(2pi)=(8xx10^(16))/(2pi)Hz`
The maximum kinetic energy of the photoelectrons is `K_(max)=hv-W`
`=(4.14xx10^(-15)eVs)xx((8xx10^(15))/(2pi)s^(-1))-2.0eV`
`=5.27eV-2.0eV=3.27eV`