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Electrons are accelerated through a potential difference of 150V. Calculate the de Broglie wavelength.

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`V=150V,h=6.62xx10^(-34)Js`
`m=9.1xx10^(-31)kg,e=1.6xx10^(-19)C`
`:.lamda=(h)/(sqrt(2Vem))=(6.62xx10^(-34))/(sqrt(2xx9.1xx10^(-31)xx1.6xx10^(-19)xx150))=1Å`
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AAKASH SERIES-DUAL NATURE OF RADIATION AND MATTER-PRACTICE EXERCISEX
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