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A bob of a simple pendulum of mass 40 mg...

A bob of a simple pendulum of mass 40 mg with a positive charge `4 xx 10^(-6)`C is oscilliating with time period `"T_(1).` An electric field of intensity `3.6 xx 10^(4)` N/c is applied vertically upwards now time period is `T_(2)`. The value of `(T_(2))/(T_(1))` is `(g = 10 m/s^(2))`

A

0.16

B

0.64

C

1.23

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
C
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