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A galvanometer of resistance 40Omega and...

A galvanometer of resistance `40Omega` and current passing through it is `100muA` per divison. The full scale has 50 divisions. If it is converted into an ammeter of range 2A by using a shunt, then the resistance of ammeter is

A

`(40)/(399)Omega`

B

`(4)/(399)Omega`

C

`0.01Omega`

D

`0.4Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
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