Home
Class 11
PHYSICS
One end of a thin uniform rod of length ...

One end of a thin uniform rod of length L and mass `M_(1)` is rivetted to the centre of a uniform circular disc of radius 'r' and mass `M_(2)` so that that both are coplanar. The centre of mass of the combination from the centre of the disc is (Assume that the point of attachment is at the origin).

A

`(L(M_(1)+M_(2)))/(2M_(1))`

B

`(LM_(1))/(2(M_(1)+M_(2)))`

C

`(2(M_(1)+M_(2)))/(LM_(1))`

D

`(2LM_(1))/((M_(1)+M_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CENTRE OF MASS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - II)|4 Videos
  • CENTRE OF MASS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - III)|7 Videos
  • CALORIMETRY

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II) (LECTURE SHEET (ADVANCED)(Matrix Type Questions)|1 Videos
  • COLLISIONS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|4 Videos

Similar Questions

Explore conceptually related problems

A circular disc of diameter d and a square plate of side d are placed as shown in fig. The centre of mass of this combination from centre of disc is (both the object are having same mass per unit area)

If a square of side R/2 is removed from a uniform circular disc of radius R as shown in the figure, the shift in centre of mass is

A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumferences of the discs touch. The centre of mass of the new disc is at a distance aR from the centre of the bigger disc. The value of a is