Prove that the function `f(x)={{:(,x+1,at ,-1 le x le0),(,-x,at,0 lt x le 1):}` is discontinuous at the point x=0 and still has the maximum and the minimum value on [-1,1].

Show that the funcation f(x)={{:(3x-2",", " when ", x le0),(x+1",", " when ", x gt 0):} is discontinuous at x =0

If f(x)={{:(,x^(2)+1,0 le x lt 1),(,-3x+5, 1 le x le 2):}

Show that the function f(x) = {{:(2x+3",",-3 le x lt -2),(x+1",",-2 le x lt 0),(x+2",",0 le x le 1):} is discontinuous at x = 0 and continuous at every point in interval [-3, 1]

If the function f(x) = {(5x-4, ",","if"0 lt x le 1),(4x^(2)+3bx, ",", "if"1 lt x le 2 ):} is continuous at every point of its domain, then the value of b is

Let f(x)={{:(1+x",", 0 le x le 2),(3-x"," ,2 lt x le 3):} find (fof) (x).

If f(x) ={(|x|,",",x lt 0),(x,",",0 le x le 1),(1,",",x gt 1):} , then f(x) is discontinuous at

If {(f(x) = 1-x), (for 0 lt x le 1),(= k , for x = 0)} is continuous at x = 0, then k =

Let f(x) ={:{(x, "for", 0 le x lt1),( 3-x,"for", 1 le x le2):} Then f(x) is

If f(x) = {{:((sqrt(4+ax)-sqrt(4-ax))/x,-1 le x lt 0),((3x+2)/(x-8), 0 le x le 1):} continuous in [-1,1] , then the value of a is

If f(x)={:{(x", for " 0 le x lt 1/2),(1-x", for " 1/2 le x lt 1):} , then