Moment of inertia of a uniform circular disc about its diameter is I. Its moment of inertia about a tangential axis parallel is its plane and passing through a point on its rim will be …………

Options

A. `(5)/(2)I`
B. `3I`
C. `(3)/(2)I`
D. `2I`

Answer

A

Explanation

Moment of inertia of disc about diameter,
`(MR^(2))/(4)=(1)/(2)`
The moment of inertia about tangential axis
`=(I)/(2)+Md^(2)`
`=(I)/(2)+MR^(2)`
`=(I)/(2)+2I" "[because MR^(2)=2I]`
`=(5I)/(2)`