The moment of inertia of a rod about an axis through its centre and perpendicular to it is `(1)/(12)ML^(2)` (where M is the mass and L, the length of the rod). The rod is bent in the middle so that the two halves make an angle `60^(@)`. The moment of inertia of the bent rod about the same axis would be..........

Options

A. `(1)/(48)ML^(2)`
B. `(1)/(12)ML^(2)`
C. `(1)/(24)ML^(2)`
D. `(ML^(2))/(8sqrt(3))`

Answer

B