In carbon monoxide molecule distance between carbon and oxygen atom is `1.1Å`. If mass of carbon atom is 12 amu and oxgyen atom is 16 amu where does the centre of mass of molecule lie?

Options

A. at a distance of `6.3Å` from a carbon atom
B. at a distance of `1Å` from a oxygen atom
C. at a distance of `0.63Å` from a carbon atom
D. at a distance of `0.12Å` from a oxygen atom

Answer

C

Explanation

`m_(1)=12,m_(2)=16`
`vec(r_(1))=0hati+0hatj,vec(r_(2))=1.1hati+0hatj`
`vecr=(m_(1)vec(r_(1))+m_(2)vec(r_(2)))/(m_(1)+m_(2))`
`=(16xx1.1)/(28)hati=0.63hati`