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A ray of light passes from glass (mu = 1...

A ray of light passes from glass (`mu` = 1.5) to water (`mu` = 1.33). The value of the critical angle of glass is ..........

A

`sin^(-1)(8/9)`

B

`sin^(-1)(sqrt(8/9))`

C

`sin^(-1)(1/2)`

D

`sin^(-1)(2/1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Refractive index n =`(1)/(sinC)implies sin C =1/n`
`therefore C=sin^(-1)(1/n)` …...........(1)
Here light ray enter from to water, so relative refractive index will be taken. `therefore n=(n_g)/(n_w)=(1.5)/(1.33)`
`therefore1/n=(1.33)/(1.5)=8/9`
From equation (1), `C=sin^(-1)(8/9)`
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