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A person measured the time period of a s...

A person measured the time period of a simple pendulum inside a stationary lift and finds it to be .T.. If the lift starts accelerating down wards with an acceleration g/3, the time period of the pendulum will be

A

`sqrt(3)T`

B

`(sqrt(3)7)/(2)`

C

`(2T)/(sqrt3)`

D

`(T)/(sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
B
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