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The potential energy of a particle (Ux)e...

The potential energy of a particle `(U_x)`executing SHM is given by

A

`U_x = K/2 (x - a)^2`

B

`U_x = K_1x + K_2x^2 + K_3 x^3`

C

`U_x = Ae^(-bx)`

D

`U_x =` constant

Text Solution

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The correct Answer is:
A
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AAKASH SERIES-SIMPLE HARMONIC MOTION -PRACTICE SHEET (EXERCISE - II)(LEVEL - II)(STRAIGHT OBJECTIVE TYPE QUESTIONS)
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