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A rigid spring of spring constant k is f...

A rigid spring of spring constant k is fixed to the ceiling of a lift. The other end of the spring is attached to a block of mass me the block hangs in equilibrium. Now the lift starts accelerating downwards with an acceleration 2g. [Assume the length of the spring to be large and its mass is negligible]. Now, 

A

The block would not perform simple harmonic motion and would stick to the ceiling

B

The block performs SHM with time period `T = 2pi sqrt(m/K)`

C

The block performs oscillatory motion but not SHM

D

The block per forms simple harmonic motion with amplitude `(2mg)/(k)`

Text Solution

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The correct Answer is:
B, D
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Knowledge Check

  • A body of mass m is attached to a spring of spring constant k which hangs from the ceiling of a elevator al rest in equilibrium. Now the elevator starts accelerating upwards with leration varying with time as a = pt+4 . where p and q are positive constant. In the from of

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    the block will perform S.H.M for all value of p and q
    B
    the block will not perform S.H.M in general for all value of p and q expect p = 0
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  • A block of mass .m. is connected to one end of a spring of .spring constant. k. The other end of the spring is fixed to a rigid support. The mass is released slowly so that the total energy of the system is then constituted by only the potentiasl energy, thn .d. is the maximum extension of the spring. Instead, if the mass is released suddenly from the same initial position, the maximum extension of the spring now is (g - acceleration due to gravity)

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  • A block of mass .m. is connected to one end of a spring of .spring constant. k. The other end of the spring is fixed to a rigid support. The mass is released slowly so that the total energy of the system is then constituted by only the potential energy, then .d. is the maximum extension of the spring. Instead, if the mass is released suddenly from the same initial position, the maximum extension of the spring now is : (g - acceleration due to gravity)

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