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The total mechanical energy of a harmoni...

The total mechanical energy of a harmonic oscillator of A =1 m and force constant ` 200 Nm^-1 is 150j`. Then

A

The minimum PE is zero

B

The maximum P E is 100 J

C

The minimum P E is 50 J

D

The maximum PE is 50 J

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The correct Answer is:
C
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AAKASH SERIES-SIMPLE HARMONIC MOTION -ADDITIONAL PRACTICE EXERCISE (STRARIGHT OBJECTIVE TYPE QUESTIONS)(LEVEL - I (MAINS))
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  2. A body executing S.H.M has a maximum acceleration equal to 48m//sec^(2...

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  3. The displacement of an object attached to a spring executing S.H.M is ...

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  4. A particle executing SHM of period 12 seconds moves through a distance...

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  5. A block of 0.5kg is placed on a horizontal platform. The system is mak...

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  6. A particle of mass 10 gm is executing S.H.M with an amplitude of 0.5 m...

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  7. A particle execute in S.H.M whose displacement equation is Y = 5 sin(1...

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  8. The force on a body executing SHM is 2N when the displacement is 2cm. ...

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  9. The total mechanical energy of a harmonic oscillator of A =1 m and ...

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  10. A particle is executing S.H.M with a frequency ‘f’. The frequency with...

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  11. A small body of mass 10 gram is making simple harmonic oscillations al...

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  13. A particle is acted by a force F = kx, where 'k' is a positive constan...

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  14. The total energy of a particle, executing simple harmonic motion is : ...

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  15. At some instant, velocity and acceleration of a particle of mass 'm' i...

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  16. The variation of PE of a simple harmonic oscillator is as shown. Then ...

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  18. A particle performs S.H.M in a straight line with time period greater ...

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  19. A particle of mass m is executing oscillations about the origin on the...

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