An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, write its symbol.

Explanation

As the ion carries one unit of negative charge, it will have one  lectron more than the number of protons
Let the number of electrons `= x`
Number of protons `=x-1`
Number of neutrons `=x+(x xx11.1)/(100)=x+0.111x=1.111x`
Solving for the value of x,
`"rotons "+ "neutrons "=" mass number "`
`x-1=1.111x=37"   "x=(38)/(2.111)=18`
Number of  lectrons = 18
Number of protons `= 18 - 1 = 17`
Number of neutrons `= 37-17 = 20` 
The ion under discussion is chloride and its symbol is `Cl^(-)`