What is the ratio between the energies of two types of radiation whose wavelengths are 6000 Å and 2000 Å respectively.

Explanation

`lambda_(1)=6000Å=6xx10^(-7)m`
`lambda_(2)=2000Å=2xx10^(-7)m`
`(E_(1))/(E_(2))=(hc)/(6xx10^(-7))xx(2xx10^(-7))/(hc)=(1)/(3)`
`therefore E_(1):E_(2)=1:3 or E_(2)=3E_(1)`