Calculate the wave number and wave length of `H_(alpha)` line in the Balmer series of hydroge emission spectrum.

Explanation

For `H_(a)` line in the Balmer series
`n_(1)=2 and n_(2)=3`
 `barv=109677((1)/(2^(2))-(1)/(3^(2)))=15,232.9cm^(-1)`
`lambda=(1)/(uspilon)=(1)/(15,232.9)=6.564xx10^(-5)cm`
`lambda=(1)/(barv)=(1)/(15,232.9)=6.564xx10^(-5)cm`
`"Wave number of "H_(alpha)" line" = 1.5239 xx 10^(4)cm^(-1)`
`"Wave length of "H_(alpha)" line "= 6564 Å`