Find the momentum of a particle whose de Broglie wavelengh is `1Å`.

Explanation

de Broglie wave length, `lambda=1Å=1.0xx10^(-10) m`
Momentum of a particle, P = ?
  `lambda=(h)/(P) or P=(h)/(lambda)=(6.625xx10^(-34)kgm^(2)s^(-1))/(1.0xx10^(-10)m)`
Momentum of a particle is `6.625 xx 10^(-24) kg ms^(-1)`