In a triangle ABC , AB = AC and ` angle A = 36^(@) ` If the internal bisector of angle C meets AB at D . Prove that AD = BC.

In triangle ABC , AB = AC , angle B = 40 ^(@) Then angle C is equal to

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

In triangle ABC , angle A = 90^@ , AD is the bisector of angle A meeting BC at D and DE bot AC at E. If AB =10cm and AC = 15 cm, then the length of DE, in cm is: triangle ABC में angle A=90^@ , AD, angle A का द्विभाजक है, जो BC से D पर मिलता है, और DE bot AC से E पर मिलता है। यदि AB = 10 cm और AC= 15 cm है, तो DE की लंबाई(cm) है,

In a tringle ABC, AB = AC and bisector of angle A meets BC at D. Prove that : (i) DeltaABD cong DeltaACD (ii) AD is perpendicular to BC.

In triangle ABC, AB = 12 cm, angle B = 60^@ , the perpendicular from A to BC meets it at D. The bisector of angle ABC meets AD at E. Then E divides AD in the ratio