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From the top of a tower of height 100m a...

From the top of a tower of height 100m a 10gm block is dropped freely and a 6gm bullet is fired vertically upwards from the foot of the tower with velocity `100ms^(-1)` simultaneously. They collide and stick together. What is the common velocity after the collision? `(g=10ms^(-2))`

Text Solution

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The correct Answer is:
27.5 m/s
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Knowledge Check

  • From the top of a tower of height 100m a 10 gm block is dropped freely and a 6gm bullet is fired vertically upwards from the foot of the tower with velocity 100ms^(-1) simultaneously. They collide and stick together. The common velocity after collision is (g = 10 ms^(-2) )

    A
    `27.5 ms^(-1)`
    B
    `150 ms^(-1)`
    C
    `40 ms^(-1)`
    D
    `100 ms^(-1)`

  • From the top of a tower of height 100m a 10 gm block is dropped freely and a 6 gm bullet is fired vertically upwards from the foot of the tower with velocity 100 ms^(-1) simultaneously. They collide and stick together. The common velocity after collision is (g= 10 ms^(-2))

    A
    `27.5 ms^(-1)`
    B
    `150 ms^(-1)`
    C
    `40 ms^(-1)`
    D
    `100 ms^(-1)`

  • From the top of a tower of height 100m a 10 gm block is dropped freely and a 6 gm bullet is fired vertically upwards from the foot of the tower with velocity 100 ms^(-1) simultaneously. They collide and stick together. The common velocity after collision is (g= 10 ms^(-2))

    A
    `27.5 ms^(-1)`
    B
    `150 ms^(-1)`
    C
    `40 ms^(-1)`
    D
    `100 ms^(-1)`

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