Two particles of masses 1kg and 3kg movetowards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of the two particles is `2ms^(-1)`, the velocity of centre of mass is `0.5ms^(-1)`. When the velocity of approach becomes `3ms^(-1)` the velocity of centre of mass is

Options

A. `0.75 ms^(-1)`
B. `0.5ms^(-1)`
C. `2.5ms^(-1)`
D. `0ms^(-1)`

Answer

B