A substance is found to have a magnetic moment of 3.9 BM. How many unpaired electrons does it contain?

A metal ion from the first transition has a magnetic moment of 3.87 B.M. How many unpaired electrons are expected to be present in the ion

Write the configuration of Ni^(2+) . How many unpaired electrons are there in the ion?

(A): Antiferromagnetic substances possess almost zero magnetic moment (R): There are no unpaired electrons in anti ferromagnetic substances

(A) The calculated spin only magnetic moment of Ti^(+2) is 1.73 BM. (R) Number of unpaired electrons in Ti^(+2) is 4.

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. Which of the following is diamagnetic ?

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. An ion of a d-block elements has magnetic moment 5.92 B.M. Select the ion among the following.

A: Oxygen molecule is paramagnetic in nature whose magnetic moment is sqrt(8) BM R: Oxygen molecule has two unpaired electrons in bonding molecular orbitals

How many unpaired electrons are present in divalent manganese ion ?