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Two bars of masses .m(1). and .m(2). con...

Two bars of masses `.m_(1).` and `.m_(2).` connected by a weightles spring of stiffness constant K as shown in figure, rest on a smooth horizontal plane. Bar 2 is shifted through a small distance x to the left and then released. Find the velocity of the centre of mass of the system after bar 1 breaks off the wall.

Text Solution

Verified by Experts

Velocity of the bar 2 at the instant of break off will be obtained as
`(1)/(2)m_(2)v_(2)^(2)=(1)/(2)kx^(2) " " v_(2)=xsqrt((k)/(m_(2)))`
The velocity of the bar 1 at that instant is zero `(v_(1) = 0)`
The velocity of the centre of mass is give by
`v_(c)=xsqrt((km_(2))/((m_(1)+m_(2))))`
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