Calculate the power of an engine which can pull a mass of 500 metric ton up an incline rising 1 in 100 with a velocity of `10 ms^(-1)`.

Explanation

`sintheta=(1)/(100).Vm//s,m=500xx10^(3)kg`
`F=mg sin theta=500xx10^(3)xx9.8xx(1)/(100)=49xx10^(3)N`
power `P=FV=49 xx 10^(3)xx10=49xx10^(4)` walt = 490 KW