Two bodies of masses `m_(1)` and `m_(2)` are moving with velocities `1ms^(-1)` and `3ms^(-1)` respecively in opposite directions. If the bodies undergo one dimensional elastic collision, the body of mass `m_(1)` comes to rest. Find the ratio of `m_(1)` and `m_(2)`.

Explanation

`u_(1)=1ms^(-1),u_(2)=-3ms^(-1),v_(1)=0`
`v_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+((2m^(2))/(m_(1)+m^(2)))u_(2)`
`0=((m_(1)-m_(2))/(m_(1)+m_(2)))1+((2m^(2))/(m_(1)+m^(2)))(-3)`
`m_(1)-m_(2)=6m_(2), " " m_(1)=7m_(2),(m_(1))/(m_(2))=(7)/(1)`