Home
Class 11
PHYSICS
A simple pendulum of length (10)/(3) met...

A simple pendulum of length `(10)/(3)` meter with a bob of mass 3 m is hanging freely from a rigid support. A bullet of mass .m. is fired with a velocity `50ms^(-1)` from the ground at an angle `.theta`. with the horizontal. When the bullet is at its highest point of its trajectory, it collides head on with the bob of the pendulum and gets embeded in the bob. After collision, if the pendulum moves through a maximum angle of `120^(@)`, then the value of `.theta.` is `(g = 10ms^(-2))`

A

`cos^(-1) (0.8)`

B

`cos^(-1)(0.6)`

C

`cos^(-1)(0.4)`

D

`cos^(-1)(0.3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    AAKASH SERIES|Exercise PRACTICE EXERCISE (SCALAR (OR) DOT PRODUCT)|9 Videos
  • WORK, POWER & ENERGY

    AAKASH SERIES|Exercise PRACTICE EXERCISE (WORK)|16 Videos
  • WORK, POWER & ENERGY

    AAKASH SERIES|Exercise EXERCISE - II (Inelastic COLLISIONS)|4 Videos
  • WORK POWER ENERGY

    AAKASH SERIES|Exercise EXERCISE - 3|61 Videos

Similar Questions

Explore conceptually related problems

A simple pendulum of length .l. carries a bob of mass m. If the breaking strenght of the string is 2 mg, the maximum angular amplitude from the vertical can be

A simple pendulum of length l carries a bob of mass m. If the breaking strength of the string is mg/2, the maximum angular amplutide from the vertical can be