ABC and ADC are two right triangles with common hypotenuse AC. Prove that `angle CAD = angle CBD.`

In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : DeltaABC ~ DeltaAMP

In the given figure, ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : (CA)/(PA)=(BC)/(MP)

In triangle ABC, AB = AC and the bisector of angle A lt intersects BC at D. Prove that, ( 1 ) triangle ADB = triangle ADC ( 2 ) angle ABC = angle ACB

triangle ABC and triangle DBC are isosceles triangles on the same base BC. Prove that line AD bisects BC at right angles

Delta ABC and Delta AMP are two right triangles right angled at B and M respectively. Prove that (i) Delta ABC ~ Delta AMP and (ii) (CA)/(PA) = (BC)/(MP) .

ABC is an isosceles triangle with AB = AC. Draw AP bot BC to show that angle B = angle C

ABCD is a quadrilateral in which AD = BC and angle DAB = angle CBA (see the given figure). Prove that ( i ) triangle ABD = triangle BAC, ( ii) BD = AC and (iii) angle ABD = angle BAC

ABC and DBC are two isosceles triangles on the same base BC (see the given figure). Show that angle ABD = angle ACD .

In Delta ABC and Delta XYZ , "if " angle A and angle X are acute angles such that cos A =cos X then show that angle A = angle X

In a right angle triangle, the sum of hypotenuous and one side is given, Prove that when the angle between them is (pi)/(3) , the area of the triangle is maximum.