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Show that the magnitude of a vector is e...

Show that the magnitude of a vector is equal to the square root of the scalar product of the vector with itself .

Text Solution

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If `vec(A)"||"vec (B)` then `theta = 0^(@)`
` :. vec(A) .vec(B) = AB cos theta = AB `
and `vec(A). Vec(A) = |vec(A)"||"vec(A)| =A^(2)`
` :. |vec(A)|= sqrt(vec(A).vec(A))`
hence the magnitude of a vector is equal to the square root of the scalar product of the vector with itself .
Magnitudeof vector is equal to the square root of the scalar product of the vector with itself .
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