A man squating on the ground gets straig...

A man squating on the ground gets straight up and stand . The force of reaction of ground on the main during the process is

constant and equal to mg in magnitude

constant and greater than mg in magnitude

variable but always greater than mg

at first greater than mg and later becomes equal to mg

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The correct Answer is:

When the man is squating on the ground , he has to balance frictional force and his weight .In this case ,
Resultant force = firction + mg
`F_(R) gt mg`
When the man gets straight up in that case friction `approx ` mg

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