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A block of weight W rests on horizontal ...

A block of weight W rests on horizontal floor with coefficient of static friction `mu` . It is desired to make the block move by applying minimum amount of force. The angle `theta ` from the horizontal at which the force should be applied and the magnitude F of the force is

A

`theta = 0,F = mu W`

B

`theta = tan^(-1) , F = (mu W)/(sqrt(1+mu^2))`

C

`theta = tan^(-1) (1/mu) , F = (muW)/(sqrt(1+mu^2))`

D

`theta = tan^(-1) ((mu)/(1+mu)),F= (muW)/(1+mu^2)`

Text Solution

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The correct Answer is:
B
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AAKASH SERIES-RIVISION EXERCISE-FRICTION (ROUGH HORIZONTAL SURFACE)
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